{"id":17937,"date":"2024-04-23T06:25:39","date_gmt":"2024-04-23T06:25:39","guid":{"rendered":"https:\/\/soicau3043.minhngocxoso.com\/?p=17937"},"modified":"2024-04-23T06:25:39","modified_gmt":"2024-04-23T06:25:39","slug":"cach-choi-va-tinh-lo-xien-2-xien-3-chinh-xac","status":"publish","type":"post","link":"https:\/\/batcaulochuan.com\/cach-choi-va-tinh-lo-xien-2-xien-3-chinh-xac\/","title":{"rendered":"C\u00e1ch ch\u01a1i v\u00e0 t\u00ednh l\u00f4 xi\u00ean 2 \u2013 xi\u00ean 3 ch\u00ednh x\u00e1c"},"content":{"rendered":"
\u0110\u00e1nh l\u00f4 xi\u00ean \u0111ang d\u1ea7n tr\u1edf n\u00ean ph\u1ed5 bi\u1ebfn v\u1edbi nh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. L\u00f4 xi\u00ean hi\u1ec7n c\u00f3 c\u00e1c lo\u1ea1i l\u00f4 xi\u00ean 2, xi\u00ean 3 v\u00e0 xi\u00ean 4. V\u1eady c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean 2 nh\u01b0 th\u1ebf n\u00e0o? C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2 v\u00e0 x\u00e1c su\u1ea5t c\u1ee7a n\u00f3 ra sao? H\u00f4m nay trong m\u1ee5c l\u00f4 \u0111\u1ec1 tr\u1ef1c tuy\u1ebfn, xin gi\u1edbi thi\u1ec7u v\u1edbi c\u00e1c b\u1ea1n v\u1ec1 l\u00f4 xi\u00ean 2 c\u0169ng nh\u01b0 c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2.<\/p>\n
Hi\u1ec7n nay c\u00f3 c\u00e1c lo\u1ea1i l\u00f4 xi\u00ean sau, b\u1ea1n c\u1ea7n bi\u1ebft c\u00e1c lo\u1ea1i l\u00f4 xi\u00ean tr\u01b0\u1edbc khi \u0111i \u0111\u1ebfn c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean.<\/b><\/p>\n V\u00ed d\u1ee5:<\/strong> l\u00f4 xi\u00ean 2: 52 \u2013 59, hay 03 \u2013 10.<\/p>\n V\u00ed d\u1ee5:<\/strong> l\u00f4 xi\u00ean 2: 52 \u2013 59 \u2013 90, hay 03 \u2013 10 \u2013 69.<\/p>\n V\u00ed d\u1ee5:<\/strong> l\u00f4 xi\u00ean 2: 52 \u2013 59 \u2013 90 \u2013 84, hay 03 \u2013 10 \u2013 69 \u2013 47.<\/p>\n V\u00ed d\u1ee5:<\/strong> l\u00f4 xi\u00ean 2: 20-02 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i hay l\u00f4 xi\u00ean 2 52-59 c\u1ee7a \u0111\u00e0i HCM.<\/p>\n <\/p>\n V\u00ed d\u1ee5:<\/strong><\/p>\n N\u1ebfu trong b\u1ea3ng k\u1ebft qu\u1ea3 c\u1ee7a \u0111\u00e0i ch\u1ecdn c\u00f3 27 gi\u1ea3i th\u01b0\u1edfng th\u00ec k\u1ebft qu\u1ea3 l\u00f4 l\u00e0 nh\u1eefng con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a 27 s\u1ed1 \u0111\u00f3.<\/p>\n T\u1ee9c l\u00e0 trong 100 s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 th\u00ec c\u00f3 27 s\u1ed1 tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 s\u1ed5 x\u1ed1. V\u1eady x\u00e1c xu\u1ea5t tr\u00fang l\u00f4 cao nh\u1ea5t l\u00e0 27%.<\/p>\n Trong tr\u01b0\u1eddng h\u1ee3p gi\u1ea3i th\u01b0\u1edfng \u1edf c\u00e1c m\u1ee5c gi\u1ea3i th\u01b0\u1edfng kh\u00e1c nhau m\u00e0 c\u00f3 nh\u1eefng s\u1ed1 cu\u1ed1i tr\u00f9ng nhau th\u00ec x\u00e1c su\u1ea5t tr\u00fang gi\u1ea3m \u0111i. Theo th\u1ef1c t\u1ebf , b\u1ec9nh qu\u00e2n ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau.<\/p>\n V\u00ec v\u1eady, c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2 l\u00e0 = 21,5% x 21,5% = 0,046. T\u1ee9c l\u00e0 x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang l\u00e0 4,6%.<\/p>\n T\u01b0\u01a1ng t\u1ef1 v\u1edbi c\u00e1c xi\u00ean 3, xi\u00ean 4<\/p>\n Qua c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2 tr\u00ean c\u00f3 th\u1ec3 th\u1ea5y mu\u1ed1n th\u1eafng b\u1ea1n c\u1ea7n ph\u1ea3i chu\u1ea9n b\u1ecb m\u1ed9t s\u1ed1 v\u1ed1n \u0111\u1ee7 v\u00e0 h\u1ee3p l\u00fd \u0111\u1ec3 \u0111\u1ec1 ph\u00f2ng r\u1ee7i ro m\u1ea5t \u0111i s\u1ed1 ti\u1ec1n c\u01b0\u1ee3c ho\u00e0n to\u00e0n.<\/p>\n \u1ede mi\u1ec1n B\u1eafc, v\u1edbi m\u1ed7i m\u1ed9t \u0111i\u1ec3m l\u00f4 tr\u00fang, ng\u01b0\u1eddi ch\u01a1i s\u1ebd thu v\u1ec1 s\u1ed1 ti\u1ec1n t\u01b0\u01a1ng \u1ee9ng l\u00e0 80.000 \u0111\u1ed3ng. N\u1ebfu trong ng\u00e0y h\u00f4m \u0111\u00f3 c\u00f3 nhi\u1ec1u gi\u1ea3i c\u00f3 2 s\u1ed1 cu\u1ed1i tr\u00f9ng v\u1edbi s\u1ed1 b\u1ea1n \u0111\u00e3 ghi l\u00e0 n l\u1ea7n th\u00ec b\u1ea1n s\u1ebd nh\u1eadn s\u1ed1 ti\u1ec1n th\u01b0\u1edfng = 80.000*n.<\/p>\n M\u1ed9t ng\u01b0\u1eddi ch\u01a1i l\u00f4 b\u00ecnh qu\u00e2n \u0111\u00e1nh 2 \u2013 3 s\u1ed1, ch\u1ec9 c\u1ea7n tr\u00fang 1 s\u1ed1 l\u00e0 c\u00f3 l\u00e3i r\u1ed3i. Khi \u0111\u00e1nh h\u00e3y \u0111\u00e1nh ch\u1eafc ch\u1eafn v\u00e0 t\u1ef1 tin v\u00e0o b\u1ea3n th\u00e2n m\u00ecnh. N\u1ebfu th\u1ea5y kh\u1ea3 n\u0103ng th\u1eafng c\u00f2n xa th\u00ec ch\u1ec9 n\u00ean \u0111\u00e1ng \u00e1ng ch\u1eebng, t\u1eebng ch\u00fat m\u1ed9t. Khi kh\u1ea3 n\u0103ng th\u1eafng cao th\u00ec \u0111\u00e1nh l\u1edbn \u0111\u1ec3 l\u1ea5y l\u1ea1i nh\u1eefng g\u00ec \u0111\u00e3 m\u1ea5t. Bi\u1ebft d\u1eebng l\u1ea1i \u0111\u00fang l\u00fac khi g\u1eb7p v\u1eadn \u0111en \u0111ang theo ch\u00e2n m\u00ecnh \u0111\u1ec3 b\u1ea3o to\u00e0n kinh t\u1ebf c\u1ee7a b\u1ea1n. Hi v\u1ecdng b\u1ea1n \u0111\u1eebng \u0111\u1eb7t n\u1eb7ng chuy\u1ec7n th\u1eafng thua.<\/p>\n V\u00ed d\u1ee5:<\/strong> l\u00f4 xi\u00ean 3 : 20-02-04 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i hay l\u00f4 xi\u00ean 3: 52-59-69 c\u1ee7a \u0111\u00e0i HCM<\/p>\n V\u00ed d\u1ee5:<\/strong><\/p>\n N\u1ebfu trong b\u1ea3ng k\u1ebft c\u1ee7a c\u1ee7a \u0111\u00e0i ch\u1ecdn c\u00f3 27 gi\u1ea3i th\u01b0\u1edfng th\u00ec k\u1ebft qu\u1ea3 l\u00f4 l\u00e0 nh\u1eefng con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a 27 s\u1ed1 \u0111\u00f3.<\/p>\n T\u1ee9c l\u00e0 trong 100 s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 th\u00ec c\u00f3 27 s\u1ed1 tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 s\u1ed5 x\u1ed1. V\u1eady x\u00e1c xu\u1ea5t tr\u00fang l\u00f4 cao nh\u1ea5t l\u00e0 27%.<\/p>\n Trong tr\u01b0\u1eddng h\u1ee3p gi\u1ea3i th\u01b0\u1edfng \u1edf c\u00e1c m\u1ee5c gi\u1ea3i th\u01b0\u1edfng kh\u00e1c nhau m\u00e0 c\u00f3 nh\u1eefng s\u1ed1 cu\u1ed1i tr\u00f9ng nhau th\u00ec x\u00e1c su\u1ea5t tr\u00fang gi\u1ea3m \u0111i. Theo th\u1ef1c t\u1ebf , b\u1ec9nh qu\u00e2n ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau.<\/p>\n Do \u0111\u00f3, ta c\u00f3 c\u00e1c c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t:<\/p>\n \u1ede mi\u1ec1n B\u1eafc, v\u1edbi m\u1ed7i m\u1ed9t \u0111i\u1ec3m l\u00f4 tr\u00fang, ng\u01b0\u1eddi ch\u01a1i s\u1ebd thu v\u1ec1 s\u1ed1 ti\u1ec1n t\u01b0\u01a1ng \u1ee9ng.<\/p>\n S\u1ed1 ti\u1ec1n n\u00e0y t\u00f9y thu\u1ed9c v\u00e0o s\u1ed1 ti\u1ec1n nh\u00e0 c\u00e1i h\u1ee9a tr\u1ea3 th\u01b0\u1edfng ban \u0111\u1ea7u. N\u1ebfu nh\u00e0 c\u00e1i h\u1ee9a tr\u1ea3 th\u01b0\u1edfng 1 \u0103n 65 th\u00ec s\u1ed1 ti\u1ec1n b\u1ea1n nh\u1eadn \u0111\u01b0\u1ee3c cho m\u1ed7i xi\u00ean 3 th\u1eafng l\u00e0 65<\/p>\n N\u1ebfu trong ng\u00e0y h\u00f4m \u0111\u00f3 c\u00f3 nhi\u1ec1u gi\u1ea3i c\u00f3 2 s\u1ed1 cu\u1ed1i tr\u00f9ng v\u1edbi s\u1ed1 b\u1ea1n \u0111\u00e3 ghi l\u00e0 n l\u1ea7n th\u00ec b\u1ea1n s\u1ebd nh\u1eadn s\u1ed1 ti\u1ec1n th\u01b0\u1edfng = 65*n.<\/p>\n Tr\u00ean \u0111\u00e2y l\u00e0 b\u00e0i vi\u1ebft gi\u1edbi thi\u1ec7u v\u1ec1 l\u00f4 xi\u00ean, l\u00f4 xi\u00ean l\u00e0 g\u00ec? C\u00e1ch ch\u01a1i l\u00f4 xi\u00ean 2 nh\u01b0 th\u1ebf n\u00e0o? C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2<\/strong> v\u00e0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2. Mong b\u1ea1n c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng th\u00e0nh c\u00f4ng trong \u0111\u00e1nh l\u00f4, \u0111\u1ec1. Ch\u00fac b\u1ea1n g\u1eb7p nhi\u1ec1u may m\u1eafn khi ch\u01a1i v\u1edbi h\u00ecnh th\u1ee9c n\u00e0y.<\/p>\nL\u00f4 xi\u00ean 2 s\u1ed1<\/strong><\/h3>\n
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L\u00f4 xi\u00ean 3 s\u1ed1<\/strong><\/h3>\n
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L\u00f4 xi\u00ean 4 s\u1ed1<\/strong><\/h3>\n
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C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2<\/strong><\/h2>\n
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C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2<\/strong><\/h2>\n
C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4:<\/strong><\/h3>\n
C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 3<\/strong><\/h2>\n
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C\u1ea3 3 s\u1ed1 l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi s\u1ed1 l\u00f4 b\u1ea1n ch\u1ecdn<\/strong><\/h3>\n
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C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/strong><\/h2>\n
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C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean 3 (tham kh\u1ea3o)<\/strong><\/h2>\n
K\u1ebft lu\u1eadn<\/strong><\/h2>\n
ch\u00ednh x\u00e1c \u0103n s\u1ed1 cao c\u1ea5p<\/h3>\n